Base | Representation |
---|---|
bin | 1100000001000011011000… |
… | …0110001101100011110001 |
3 | 1201210002001211001012100112 |
4 | 3000100312012031203301 |
5 | 3212432120103004221 |
6 | 44033340245431105 |
7 | 2532360205343351 |
oct | 300206606154361 |
9 | 51702054035315 |
10 | 13212227000561 |
11 | 4234301777436 |
12 | 159475010b495 |
13 | 74aba518b064 |
14 | 339691d34b61 |
15 | 17da3126b15b |
hex | c043618d8f1 |
13212227000561 has 2 divisors, whose sum is σ = 13212227000562. Its totient is φ = 13212227000560.
The previous prime is 13212227000527. The next prime is 13212227000689. The reversal of 13212227000561 is 16500072221231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12896135672161 + 316091328400 = 3591119^2 + 562220^2 .
It is a cyclic number.
It is not a de Polignac number, because 13212227000561 - 234 = 13195047131377 is a prime.
It is not a weakly prime, because it can be changed into another prime (13212227000501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606113500280 + 6606113500281.
It is an arithmetic number, because the mean of its divisors is an integer number (6606113500281).
Almost surely, 213212227000561 is an apocalyptic number.
It is an amenable number.
13212227000561 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212227000561 is an equidigital number, since it uses as much as digits as its factorization.
13212227000561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 13212227000561 its reverse (16500072221231), we get a palindrome (29712299221792).
The spelling of 13212227000561 in words is "thirteen trillion, two hundred twelve billion, two hundred twenty-seven million, five hundred sixty-one", and thus it is an aban number.
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