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132122300111233 is a prime number
BaseRepresentation
bin11110000010101000011110…
…110000111101100110000001
3122022210202202021002111200021
4132002220132300331212001
5114304142432312024413
61145000051410453441
736554343523045555
oct3602503660754601
9568722667074607
10132122300111233
1139109830a9a803
121299a22ab94281
1358951056b7583
14248aa79651865
151041c0e42118d
hex782a1ec3d981

132122300111233 has 2 divisors, whose sum is σ = 132122300111234. Its totient is φ = 132122300111232.

The previous prime is 132122300111173. The next prime is 132122300111239. The reversal of 132122300111233 is 332111003221231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115079835535729 + 17042464575504 = 10727527^2 + 4128252^2 .

It is a cyclic number.

It is not a de Polignac number, because 132122300111233 - 221 = 132122298014081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132122300111198 and 132122300111207.

It is not a weakly prime, because it can be changed into another prime (132122300111239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061150055616 + 66061150055617.

It is an arithmetic number, because the mean of its divisors is an integer number (66061150055617).

Almost surely, 2132122300111233 is an apocalyptic number.

It is an amenable number.

132122300111233 is a deficient number, since it is larger than the sum of its proper divisors (1).

132122300111233 is an equidigital number, since it uses as much as digits as its factorization.

132122300111233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 132122300111233 its reverse (332111003221231), we get a palindrome (464233303332464).

The spelling of 132122300111233 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, three hundred million, one hundred eleven thousand, two hundred thirty-three".