Base | Representation |
---|---|
bin | 111101100001100011… |
… | …1000101001000110011 |
3 | 110122000211122222001022 |
4 | 1323003013011020303 |
5 | 4131041320311201 |
6 | 140410214130055 |
7 | 12355055066621 |
oct | 1730307051063 |
9 | 418024588038 |
10 | 132122432051 |
11 | 5103a739805 |
12 | 2173365092b |
13 | c5c7817a9c |
14 | 6575314511 |
15 | 368435c41b |
hex | 1ec31c5233 |
132122432051 has 2 divisors, whose sum is σ = 132122432052. Its totient is φ = 132122432050.
The previous prime is 132122432033. The next prime is 132122432059. The reversal of 132122432051 is 150234221231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132122432051 is a prime.
It is a super-2 number, since 2×1321224320512 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132122432051.
It is not a weakly prime, because it can be changed into another prime (132122432059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061216025 + 66061216026.
It is an arithmetic number, because the mean of its divisors is an integer number (66061216026).
Almost surely, 2132122432051 is an apocalyptic number.
132122432051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132122432051 is an equidigital number, since it uses as much as digits as its factorization.
132122432051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 132122432051 its reverse (150234221231), we get a palindrome (282356653282).
The spelling of 132122432051 in words is "one hundred thirty-two billion, one hundred twenty-two million, four hundred thirty-two thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •