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132122432051 is a prime number
BaseRepresentation
bin111101100001100011…
…1000101001000110011
3110122000211122222001022
41323003013011020303
54131041320311201
6140410214130055
712355055066621
oct1730307051063
9418024588038
10132122432051
115103a739805
122173365092b
13c5c7817a9c
146575314511
15368435c41b
hex1ec31c5233

132122432051 has 2 divisors, whose sum is σ = 132122432052. Its totient is φ = 132122432050.

The previous prime is 132122432033. The next prime is 132122432059. The reversal of 132122432051 is 150234221231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132122432051 is a prime.

It is a super-2 number, since 2×1321224320512 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132122432051.

It is not a weakly prime, because it can be changed into another prime (132122432059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061216025 + 66061216026.

It is an arithmetic number, because the mean of its divisors is an integer number (66061216026).

Almost surely, 2132122432051 is an apocalyptic number.

132122432051 is a deficient number, since it is larger than the sum of its proper divisors (1).

132122432051 is an equidigital number, since it uses as much as digits as its factorization.

132122432051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 132122432051 its reverse (150234221231), we get a palindrome (282356653282).

The spelling of 132122432051 in words is "one hundred thirty-two billion, one hundred twenty-two million, four hundred thirty-two thousand, fifty-one".