Base | Representation |
---|---|
bin | 11000100111000001… |
… | …01101100000100011 |
3 | 1021002210011112111111 |
4 | 30103200231200203 |
5 | 204024313302003 |
6 | 10023012124151 |
7 | 645261135550 |
oct | 142340554043 |
9 | 37083145444 |
10 | 13212244003 |
11 | 566aa70522 |
12 | 2688906657 |
13 | 132735507a |
14 | 8d4a17a27 |
15 | 524dc8e6d |
hex | 31382d823 |
13212244003 has 4 divisors (see below), whose sum is σ = 15099707440. Its totient is φ = 11324780568.
The previous prime is 13212243983. The next prime is 13212244007. The reversal of 13212244003 is 30044221231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13212244003 - 25 = 13212243971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13212244007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 943731708 + ... + 943731721.
It is an arithmetic number, because the mean of its divisors is an integer number (3774926860).
Almost surely, 213212244003 is an apocalyptic number.
13212244003 is a deficient number, since it is larger than the sum of its proper divisors (1887463437).
13212244003 is an equidigital number, since it uses as much as digits as its factorization.
13212244003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1887463436.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 13212244003 its reverse (30044221231), we get a palindrome (43256465234).
The spelling of 13212244003 in words is "thirteen billion, two hundred twelve million, two hundred forty-four thousand, three".
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