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13212244341281 is a prime number
BaseRepresentation
bin1100000001000011011100…
…1000010111001000100001
31201210002010000200012100102
43000100313020113020201
53212432134022410111
644033342105232145
72532360505625366
oct300206710271041
951702100605312
1013212244341281
114234310540807
121594755a92655
1374aba894cc3b
1433969436a46d
1517da32a4413b
hexc0437217221

13212244341281 has 2 divisors, whose sum is σ = 13212244341282. Its totient is φ = 13212244341280.

The previous prime is 13212244341259. The next prime is 13212244341341. The reversal of 13212244341281 is 18214344221231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9739299016225 + 3472945325056 = 3120785^2 + 1863584^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13212244341281 is a prime.

It is a super-2 number, since 2×132122443412812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13212244341481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606122170640 + 6606122170641.

It is an arithmetic number, because the mean of its divisors is an integer number (6606122170641).

Almost surely, 213212244341281 is an apocalyptic number.

It is an amenable number.

13212244341281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212244341281 is an equidigital number, since it uses as much as digits as its factorization.

13212244341281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 73728, while the sum is 38.

The spelling of 13212244341281 in words is "thirteen trillion, two hundred twelve billion, two hundred forty-four million, three hundred forty-one thousand, two hundred eighty-one".