Base | Representation |
---|---|
bin | 1100000001000011011100… |
… | …1000010111001000100001 |
3 | 1201210002010000200012100102 |
4 | 3000100313020113020201 |
5 | 3212432134022410111 |
6 | 44033342105232145 |
7 | 2532360505625366 |
oct | 300206710271041 |
9 | 51702100605312 |
10 | 13212244341281 |
11 | 4234310540807 |
12 | 1594755a92655 |
13 | 74aba894cc3b |
14 | 33969436a46d |
15 | 17da32a4413b |
hex | c0437217221 |
13212244341281 has 2 divisors, whose sum is σ = 13212244341282. Its totient is φ = 13212244341280.
The previous prime is 13212244341259. The next prime is 13212244341341. The reversal of 13212244341281 is 18214344221231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9739299016225 + 3472945325056 = 3120785^2 + 1863584^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13212244341281 is a prime.
It is a super-2 number, since 2×132122443412812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13212244341481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606122170640 + 6606122170641.
It is an arithmetic number, because the mean of its divisors is an integer number (6606122170641).
Almost surely, 213212244341281 is an apocalyptic number.
It is an amenable number.
13212244341281 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212244341281 is an equidigital number, since it uses as much as digits as its factorization.
13212244341281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 73728, while the sum is 38.
The spelling of 13212244341281 in words is "thirteen trillion, two hundred twelve billion, two hundred forty-four million, three hundred forty-one thousand, two hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •