Base | Representation |
---|---|
bin | 11110000010101001001001… |
… | …001001111110000110110001 |
3 | 122022210211120211100010222101 |
4 | 132002221021021332012301 |
5 | 114304200411343410001 |
6 | 1145000250134140401 |
7 | 36554400250121425 |
oct | 3602511111760661 |
9 | 568724524303871 |
10 | 132123011310001 |
11 | 3910a066498988 |
12 | 1299a3a91b1701 |
13 | 58951b9b4804a |
14 | 248ab05ca2b85 |
15 | 1041c51aa6a01 |
hex | 782a4927e1b1 |
132123011310001 has 2 divisors, whose sum is σ = 132123011310002. Its totient is φ = 132123011310000.
The previous prime is 132123011309921. The next prime is 132123011310029. The reversal of 132123011310001 is 100013110321231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132044919566400 + 78091743601 = 11491080^2 + 279449^2 .
It is a cyclic number.
It is not a de Polignac number, because 132123011310001 - 215 = 132123011277233 is a prime.
It is not a weakly prime, because it can be changed into another prime (132123071310001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061505655000 + 66061505655001.
It is an arithmetic number, because the mean of its divisors is an integer number (66061505655001).
Almost surely, 2132123011310001 is an apocalyptic number.
It is an amenable number.
132123011310001 is a deficient number, since it is larger than the sum of its proper divisors (1).
132123011310001 is an equidigital number, since it uses as much as digits as its factorization.
132123011310001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 132123011310001 its reverse (100013110321231), we get a palindrome (232136121631232).
The spelling of 132123011310001 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, eleven million, three hundred ten thousand, one".
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