13212311115434 has 4 divisors (see below), whose sum is σ = 19818466673154. Its totient is φ = 6606155557716.

The previous prime is 13212311115373. The next prime is 13212311115473. The reversal of 13212311115434 is 43451111321231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8801030022409 + 4411281093025 = 2966653^2 + 2100305^2 .

It is a super-2 number, since 2×13212311115434² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13212311115434.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303077778857 + ... + 3303077778860.

Almost surely, 2^{13212311115434} is an apocalyptic number.

13212311115434 is a deficient number, since it is larger than the sum of its proper divisors (6606155557720).

13212311115434 is an equidigital number, since it uses as much as digits as its factorization.

13212311115434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6606155557719.

The product of its digits is 8640, while the sum is 32.

Adding to 13212311115434 its reverse (43451111321231), we get a palindrome (56663422436665).

The spelling of 13212311115434 in words is "thirteen trillion, two hundred twelve billion, three hundred eleven million, one hundred fifteen thousand, four hundred thirty-four".