Base | Representation |
---|---|
bin | 11000100111000010… |
… | …00000010101001001 |
3 | 1021002210022110020211 |
4 | 30103201000111021 |
5 | 204024323233342 |
6 | 10023013521121 |
7 | 645261606403 |
oct | 142341002511 |
9 | 37083273224 |
10 | 13212321097 |
11 | 5670013438 |
12 | 26889431a1 |
13 | 13273811a1 |
14 | 8d4a37b73 |
15 | 524de1c17 |
hex | 313840549 |
13212321097 has 2 divisors, whose sum is σ = 13212321098. Its totient is φ = 13212321096.
The previous prime is 13212321077. The next prime is 13212321113. The reversal of 13212321097 is 79012321231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12227051776 + 985269321 = 110576^2 + 31389^2 .
It is a cyclic number.
It is not a de Polignac number, because 13212321097 - 215 = 13212288329 is a prime.
It is a super-3 number, since 3×132123210973 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13212321037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606160548 + 6606160549.
It is an arithmetic number, because the mean of its divisors is an integer number (6606160549).
Almost surely, 213212321097 is an apocalyptic number.
It is an amenable number.
13212321097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212321097 is an equidigital number, since it uses as much as digits as its factorization.
13212321097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 31.
The spelling of 13212321097 in words is "thirteen billion, two hundred twelve million, three hundred twenty-one thousand, ninety-seven".
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