Base | Representation |
---|---|
bin | 111101100001100110… |
… | …1100011110000110001 |
3 | 110122000221212020200101 |
4 | 1323003031203300301 |
5 | 4131042234132403 |
6 | 140410314352401 |
7 | 12355105402135 |
oct | 1730315436061 |
9 | 418027766611 |
10 | 132124130353 |
11 | 51040699766 |
12 | 2173412b701 |
13 | c5c7c90ab7 |
14 | 65756373c5 |
15 | 368459571d |
hex | 1ec3363c31 |
132124130353 has 2 divisors, whose sum is σ = 132124130354. Its totient is φ = 132124130352.
The previous prime is 132124130321. The next prime is 132124130371. The reversal of 132124130353 is 353031421231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83525046049 + 48599084304 = 289007^2 + 220452^2 .
It is a cyclic number.
It is not a de Polignac number, because 132124130353 - 25 = 132124130321 is a prime.
It is not a weakly prime, because it can be changed into another prime (132124133353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062065176 + 66062065177.
It is an arithmetic number, because the mean of its divisors is an integer number (66062065177).
Almost surely, 2132124130353 is an apocalyptic number.
It is an amenable number.
132124130353 is a deficient number, since it is larger than the sum of its proper divisors (1).
132124130353 is an equidigital number, since it uses as much as digits as its factorization.
132124130353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 132124130353 its reverse (353031421231), we get a palindrome (485155551584).
The spelling of 132124130353 in words is "one hundred thirty-two billion, one hundred twenty-four million, one hundred thirty thousand, three hundred fifty-three".
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