Base | Representation |
---|---|
bin | 11110000010101010010111… |
… | …001111001111000110001001 |
3 | 122022210221222010100012110221 |
4 | 132002222113033033012021 |
5 | 114304211102224010121 |
6 | 1145001024132110041 |
7 | 36554444565013552 |
oct | 3602522717170611 |
9 | 568727863305427 |
10 | 132124321313161 |
11 | 3910a6789a8721 |
12 | 1299a6b3a65321 |
13 | 5895368376148 |
14 | 248abcbc69329 |
15 | 1041ccbac0b41 |
hex | 782a973cf189 |
132124321313161 has 2 divisors, whose sum is σ = 132124321313162. Its totient is φ = 132124321313160.
The previous prime is 132124321313099. The next prime is 132124321313251. The reversal of 132124321313161 is 161313123421231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83871070353225 + 48253250959936 = 9158115^2 + 6946456^2 .
It is a cyclic number.
It is not a de Polignac number, because 132124321313161 - 29 = 132124321312649 is a prime.
It is not a weakly prime, because it can be changed into another prime (132124321310161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062160656580 + 66062160656581.
It is an arithmetic number, because the mean of its divisors is an integer number (66062160656581).
Almost surely, 2132124321313161 is an apocalyptic number.
It is an amenable number.
132124321313161 is a deficient number, since it is larger than the sum of its proper divisors (1).
132124321313161 is an equidigital number, since it uses as much as digits as its factorization.
132124321313161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 34.
Adding to 132124321313161 its reverse (161313123421231), we get a palindrome (293437444734392).
The spelling of 132124321313161 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, three hundred twenty-one million, three hundred thirteen thousand, one hundred sixty-one".
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