Base | Representation |
---|---|
bin | 11110000010101011000000… |
… | …010011010101010001100011 |
3 | 122022211000202010200222010112 |
4 | 132002223000103111101203 |
5 | 114304214010111043044 |
6 | 1145001220342321535 |
7 | 36554500631631326 |
oct | 3602530023252143 |
9 | 568730663628115 |
10 | 132125010252899 |
11 | 3910a9a1883304 |
12 | 1299a8667292ab |
13 | 58954480121b1 |
14 | 248ac555647bd |
15 | 1041d1c30b09e |
hex | 782ac04d5463 |
132125010252899 has 2 divisors, whose sum is σ = 132125010252900. Its totient is φ = 132125010252898.
The previous prime is 132125010252847. The next prime is 132125010253043. The reversal of 132125010252899 is 998252010521231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132125010252899 is a prime.
It is not a weakly prime, because it can be changed into another prime (132125010252299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062505126449 + 66062505126450.
It is an arithmetic number, because the mean of its divisors is an integer number (66062505126450).
Almost surely, 2132125010252899 is an apocalyptic number.
132125010252899 is a deficient number, since it is larger than the sum of its proper divisors (1).
132125010252899 is an equidigital number, since it uses as much as digits as its factorization.
132125010252899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 50.
The spelling of 132125010252899 in words is "one hundred thirty-two trillion, one hundred twenty-five billion, ten million, two hundred fifty-two thousand, eight hundred ninety-nine".
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