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1321304004353 is a prime number
BaseRepresentation
bin10011001110100011110…
…110110001011100000001
311200022111221121000011102
4103032203312301130001
5133122012311114403
62450555414224145
7164314100504264
oct23164366613401
94608457530142
101321304004353
1146a3a8733a63
121940b2055055
13977a19ac888
1447d46b14cdb
15245843c2b88
hex133a3db1701

1321304004353 has 2 divisors, whose sum is σ = 1321304004354. Its totient is φ = 1321304004352.

The previous prime is 1321304004313. The next prime is 1321304004359. The reversal of 1321304004353 is 3534004031231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 993745809424 + 327558194929 = 996868^2 + 572327^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321304004353 - 210 = 1321304003329 is a prime.

It is not a weakly prime, because it can be changed into another prime (1321304004359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660652002176 + 660652002177.

It is an arithmetic number, because the mean of its divisors is an integer number (660652002177).

Almost surely, 21321304004353 is an apocalyptic number.

It is an amenable number.

1321304004353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321304004353 is an equidigital number, since it uses as much as digits as its factorization.

1321304004353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 1321304004353 its reverse (3534004031231), we get a palindrome (4855308035584).

The spelling of 1321304004353 in words is "one trillion, three hundred twenty-one billion, three hundred four million, four thousand, three hundred fifty-three".