Base | Representation |
---|---|
bin | 11110000010110000101100… |
… | …000000001000111001101011 |
3 | 122022211121111101110100022121 |
4 | 132002300230000020321223 |
5 | 114304314004201044412 |
6 | 1145004110034532111 |
7 | 36555105064002061 |
oct | 3602605400107153 |
9 | 568747441410277 |
10 | 132131112128107 |
11 | 39112543166484 |
12 | 1299ba8a137037 |
13 | 5895bab22a141 |
14 | 248b273ad2031 |
15 | 1042077d69107 |
hex | 782c2c008e6b |
132131112128107 has 2 divisors, whose sum is σ = 132131112128108. Its totient is φ = 132131112128106.
The previous prime is 132131112128039. The next prime is 132131112128129. The reversal of 132131112128107 is 701821211131231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132131112128107 - 235 = 132096752389739 is a prime.
It is not a weakly prime, because it can be changed into another prime (132131112128707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065556064053 + 66065556064054.
It is an arithmetic number, because the mean of its divisors is an integer number (66065556064054).
Almost surely, 2132131112128107 is an apocalyptic number.
132131112128107 is a deficient number, since it is larger than the sum of its proper divisors (1).
132131112128107 is an equidigital number, since it uses as much as digits as its factorization.
132131112128107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 34.
Adding to 132131112128107 its reverse (701821211131231), we get a palindrome (833952323259338).
The spelling of 132131112128107 in words is "one hundred thirty-two trillion, one hundred thirty-one billion, one hundred twelve million, one hundred twenty-eight thousand, one hundred seven".
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