Base | Representation |
---|---|
bin | 1100000001000111000011… |
… | …1000101111001100000011 |
3 | 1201210011121112222121210120 |
4 | 3000101300320233030003 |
5 | 3212441130102332120 |
6 | 44034022202031323 |
7 | 2532423513063114 |
oct | 300216070571403 |
9 | 51704545877716 |
10 | 13213213324035 |
11 | 42347684a98aa |
12 | 15949864a8543 |
13 | 74b00161a10a |
14 | 339746d2220b |
15 | 17da8cb4a140 |
hex | c0470e2f303 |
13213213324035 has 32 divisors (see below), whose sum is σ = 21164582299392. Its totient is φ = 7039237495680.
The previous prime is 13213213323991. The next prime is 13213213324057. The reversal of 13213213324035 is 53042331231231.
It is not a de Polignac number, because 13213213324035 - 212 = 13213213319939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13213213323987 and 13213213324005.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52895580 + ... + 53144790.
It is an arithmetic number, because the mean of its divisors is an integer number (661393196856).
Almost surely, 213213213324035 is an apocalyptic number.
13213213324035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13213213324035 is a deficient number, since it is larger than the sum of its proper divisors (7951368975357).
13213213324035 is a wasteful number, since it uses less digits than its factorization.
13213213324035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253123.
The product of its (nonzero) digits is 38880, while the sum is 33.
Adding to 13213213324035 its reverse (53042331231231), we get a palindrome (66255544555266).
The spelling of 13213213324035 in words is "thirteen trillion, two hundred thirteen billion, two hundred thirteen million, three hundred twenty-four thousand, thirty-five".
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