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132132505231241 is a prime number
BaseRepresentation
bin11110000010110001111111…
…000010011001111110001001
3122022211202002110211022112222
4132002301333002121332021
5114304324332314344431
61145004500201543425
736555154441121204
oct3602617702317611
9568752073738488
10132132505231241
1139113098574489
12129a01b87a4b75
135896070a32618
14248b366b2a93b
15104210a2ea57b
hex782c7f099f89

132132505231241 has 2 divisors, whose sum is σ = 132132505231242. Its totient is φ = 132132505231240.

The previous prime is 132132505231219. The next prime is 132132505231249. The reversal of 132132505231241 is 142132505231231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126843816150016 + 5288689081225 = 11262496^2 + 2299715^2 .

It is a cyclic number.

It is not a de Polignac number, because 132132505231241 - 230 = 132131431489417 is a prime.

It is not a weakly prime, because it can be changed into another prime (132132505231249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066252615620 + 66066252615621.

It is an arithmetic number, because the mean of its divisors is an integer number (66066252615621).

Almost surely, 2132132505231241 is an apocalyptic number.

It is an amenable number.

132132505231241 is a deficient number, since it is larger than the sum of its proper divisors (1).

132132505231241 is an equidigital number, since it uses as much as digits as its factorization.

132132505231241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 132132505231241 in words is "one hundred thirty-two trillion, one hundred thirty-two billion, five hundred five million, two hundred thirty-one thousand, two hundred forty-one".