Base | Representation |
---|---|
bin | 1100000001000111100000… |
… | …0101001010110001000001 |
3 | 1201210011220222002202222020 |
4 | 3000101320011022301001 |
5 | 3212441402002220413 |
6 | 44034042153032053 |
7 | 2532426510025611 |
oct | 300217005126101 |
9 | 51704828082866 |
10 | 13213334023233 |
11 | 423481a648a03 |
12 | 15949ba9b5629 |
13 | 74b02062a366 |
14 | 339758d80a41 |
15 | 17da9853cc23 |
hex | c047814ac41 |
13213334023233 has 8 divisors (see below), whose sum is σ = 17618118839328. Its totient is φ = 8808719277984.
The previous prime is 13213334023223. The next prime is 13213334023259. The reversal of 13213334023233 is 33232043331231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13213334023233 - 210 = 13213334022209 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13213334023194 and 13213334023203.
It is not an unprimeable number, because it can be changed into a prime (13213334023223) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42336316 + ... + 42647277.
It is an arithmetic number, because the mean of its divisors is an integer number (2202264854916).
Almost surely, 213213334023233 is an apocalyptic number.
It is an amenable number.
13213334023233 is a deficient number, since it is larger than the sum of its proper divisors (4404784816095).
13213334023233 is an equidigital number, since it uses as much as digits as its factorization.
13213334023233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85035423.
The product of its (nonzero) digits is 69984, while the sum is 33.
Adding to 13213334023233 its reverse (33232043331231), we get a palindrome (46445377354464).
The spelling of 13213334023233 in words is "thirteen trillion, two hundred thirteen billion, three hundred thirty-four million, twenty-three thousand, two hundred thirty-three".
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