Base | Representation |
---|---|
bin | 11110000010110100100110… |
… | …110100000100011100100011 |
3 | 122022212000100122101200121021 |
4 | 132002310212310010130203 |
5 | 114304401113412422342 |
6 | 1145010043353110311 |
7 | 36555314260466263 |
oct | 3602644664043443 |
9 | 568760318350537 |
10 | 132135320045347 |
11 | 3911430244aa33 |
12 | 129a08633b8397 |
13 | 58963cbc486b8 |
14 | 248b5528c97a3 |
15 | 10422224ae567 |
hex | 782d26d04723 |
132135320045347 has 2 divisors, whose sum is σ = 132135320045348. Its totient is φ = 132135320045346.
The previous prime is 132135320045329. The next prime is 132135320045359. The reversal of 132135320045347 is 743540023531231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132135320045347 - 211 = 132135320043299 is a prime.
It is not a weakly prime, because it can be changed into another prime (132135320045317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66067660022673 + 66067660022674.
It is an arithmetic number, because the mean of its divisors is an integer number (66067660022674).
Almost surely, 2132135320045347 is an apocalyptic number.
132135320045347 is a deficient number, since it is larger than the sum of its proper divisors (1).
132135320045347 is an equidigital number, since it uses as much as digits as its factorization.
132135320045347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 43.
Adding to 132135320045347 its reverse (743540023531231), we get a palindrome (875675343576578).
The spelling of 132135320045347 in words is "one hundred thirty-two trillion, one hundred thirty-five billion, three hundred twenty million, forty-five thousand, three hundred forty-seven".
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