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132137761474633 is a prime number
BaseRepresentation
bin11110000010110110111000…
…010101011000100001001001
3122022212020122210101010222011
4132002312320111120201021
5114304421113414142013
61145011125525255521
736555431624343025
oct3602667025304111
9568766583333864
10132137761474633
1139115345589992
12129a1224b645a1
1358966ca9ab605
14248b704c51385
1510423169bac3d
hex782db8558849

132137761474633 has 2 divisors, whose sum is σ = 132137761474634. Its totient is φ = 132137761474632.

The previous prime is 132137761474571. The next prime is 132137761474643. The reversal of 132137761474633 is 336474167731231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127272084309049 + 4865677165584 = 11281493^2 + 2205828^2 .

It is an emirp because it is prime and its reverse (336474167731231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132137761474633 is a prime.

It is not a weakly prime, because it can be changed into another prime (132137761474643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66068880737316 + 66068880737317.

It is an arithmetic number, because the mean of its divisors is an integer number (66068880737317).

Almost surely, 2132137761474633 is an apocalyptic number.

It is an amenable number.

132137761474633 is a deficient number, since it is larger than the sum of its proper divisors (1).

132137761474633 is an equidigital number, since it uses as much as digits as its factorization.

132137761474633 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32006016, while the sum is 58.

The spelling of 132137761474633 in words is "one hundred thirty-two trillion, one hundred thirty-seven billion, seven hundred sixty-one million, four hundred seventy-four thousand, six hundred thirty-three".