Base | Representation |
---|---|
bin | 10011001110101001111… |
… | …000001011001001111011 |
3 | 11200022202222200220100002 |
4 | 103032221320023021323 |
5 | 133122214142111011 |
6 | 2451013423503215 |
7 | 164316435321536 |
oct | 23165170131173 |
9 | 4608688626302 |
10 | 1321405035131 |
11 | 46a44a769975 |
12 | 19411ba57b0b |
13 | 977b98c45bc |
14 | 47d562d3a1d |
15 | 2458d1ccc3b |
hex | 133a9e0b27b |
1321405035131 has 2 divisors, whose sum is σ = 1321405035132. Its totient is φ = 1321405035130.
The previous prime is 1321405035121. The next prime is 1321405035161. The reversal of 1321405035131 is 1315305041231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1321405035131 - 210 = 1321405034107 is a prime.
It is a super-2 number, since 2×13214050351312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1321405035094 and 1321405035103.
It is not a weakly prime, because it can be changed into another prime (1321405035121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660702517565 + 660702517566.
It is an arithmetic number, because the mean of its divisors is an integer number (660702517566).
Almost surely, 21321405035131 is an apocalyptic number.
1321405035131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321405035131 is an equidigital number, since it uses as much as digits as its factorization.
1321405035131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 29.
The spelling of 1321405035131 in words is "one trillion, three hundred twenty-one billion, four hundred five million, thirty-five thousand, one hundred thirty-one".
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