Base | Representation |
---|---|
bin | 11000100111001111… |
… | …10111100001101010 |
3 | 1021002220200211221102 |
4 | 30103213313201222 |
5 | 204030303320132 |
6 | 10023120241402 |
7 | 645313111214 |
oct | 142347674152 |
9 | 37086624842 |
10 | 13214120042 |
11 | 5671031a72 |
12 | 2689470262 |
13 | 1327860c56 |
14 | 8d4d855b4 |
15 | 525149c62 |
hex | 3139f786a |
13214120042 has 4 divisors (see below), whose sum is σ = 19821180066. Its totient is φ = 6607060020.
The previous prime is 13214120041. The next prime is 13214120069. The reversal of 13214120042 is 24002141231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24002141231 = 11621 ⋅2065411.
It can be written as a sum of positive squares in only one way, i.e., 13158154681 + 55965361 = 114709^2 + 7481^2 .
It is a super-2 number, since 2×132141200422 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13214119996 and 13214120023.
It is not an unprimeable number, because it can be changed into a prime (13214120041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303530009 + ... + 3303530012.
Almost surely, 213214120042 is an apocalyptic number.
13214120042 is a deficient number, since it is larger than the sum of its proper divisors (6607060024).
13214120042 is an equidigital number, since it uses as much as digits as its factorization.
13214120042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6607060023.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13214120042 its reverse (24002141231), we get a palindrome (37216261273).
The spelling of 13214120042 in words is "thirteen billion, two hundred fourteen million, one hundred twenty thousand, forty-two".
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