13214134251033 has 4 divisors (see below), whose sum is σ = 17618845668048. Its totient is φ = 8809422834020.

The previous prime is 13214134251029. The next prime is 13214134251041. The reversal of 13214134251033 is 33015243141231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13214134251033 - 2² = 13214134251029 is a prime.

It is a super-2 number, since 2×13214134251033² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13214134250985 and 13214134251003.

It is not an unprimeable number, because it can be changed into a prime (13214134251133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2202355708503 + ... + 2202355708508.

It is an arithmetic number, because the mean of its divisors is an integer number (4404711417012).

Almost surely, 2^{13214134251033} is an apocalyptic number.

It is an amenable number.

13214134251033 is a deficient number, since it is larger than the sum of its proper divisors (4404711417015).

13214134251033 is an equidigital number, since it uses as much as digits as its factorization.

13214134251033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4404711417014.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 13214134251033 its reverse (33015243141231), we get a palindrome (46229377392264).

The spelling of 13214134251033 in words is "thirteen trillion, two hundred fourteen billion, one hundred thirty-four million, two hundred fifty-one thousand, thirty-three".