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13214401423411 = 96667136700233
BaseRepresentation
bin1100000001001011011110…
…1100111110100000110011
31201210021200100121022202011
43000102313230332200303
53213001043231022121
644034340123103351
72532465120544516
oct300226754764063
951707610538664
1013214401423411
114235218117511
121595058371b57
1374b1608058b6
1433981aa34d7d
1517db0c0d47e1
hexc04b7b3e833

13214401423411 has 4 divisors (see below), whose sum is σ = 13214538220312. Its totient is φ = 13214264626512.

The previous prime is 13214401423369. The next prime is 13214401423439. The reversal of 13214401423411 is 11432410441231.

13214401423411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13214401423411 - 29 = 13214401422899 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13214401423441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68253450 + ... + 68446783.

It is an arithmetic number, because the mean of its divisors is an integer number (3303634555078).

Almost surely, 213214401423411 is an apocalyptic number.

13214401423411 is a deficient number, since it is larger than the sum of its proper divisors (136796901).

13214401423411 is an equidigital number, since it uses as much as digits as its factorization.

13214401423411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 136796900.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13214401423411 its reverse (11432410441231), we get a palindrome (24646811864642).

The spelling of 13214401423411 in words is "thirteen trillion, two hundred fourteen billion, four hundred one million, four hundred twenty-three thousand, four hundred eleven".

Divisors: 1 96667 136700233 13214401423411