Base | Representation |
---|---|
bin | 1100000001001011100000… |
… | …1101110011101111010001 |
3 | 1201210021200221210120210221 |
4 | 3000102320031303233101 |
5 | 3213001102431430113 |
6 | 44034341031353041 |
7 | 2532465253651642 |
oct | 300227015635721 |
9 | 51707627716727 |
10 | 13214410030033 |
11 | 4235221a65823 |
12 | 159505b222781 |
13 | 74b16252a184 |
14 | 33981bc356c9 |
15 | 17db0cc3498d |
hex | c04b8373bd1 |
13214410030033 has 2 divisors, whose sum is σ = 13214410030034. Its totient is φ = 13214410030032.
The previous prime is 13214410029941. The next prime is 13214410030039. The reversal of 13214410030033 is 33003001441231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13210266275649 + 4143754384 = 3634593^2 + 64372^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13214410030033 is a prime.
It is not a weakly prime, because it can be changed into another prime (13214410030039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607205015016 + 6607205015017.
It is an arithmetic number, because the mean of its divisors is an integer number (6607205015017).
Almost surely, 213214410030033 is an apocalyptic number.
It is an amenable number.
13214410030033 is a deficient number, since it is larger than the sum of its proper divisors (1).
13214410030033 is an equidigital number, since it uses as much as digits as its factorization.
13214410030033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13214410030033 its reverse (33003001441231), we get a palindrome (46217411471264).
The spelling of 13214410030033 in words is "thirteen trillion, two hundred fourteen billion, four hundred ten million, thirty thousand, thirty-three".
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