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1321443323241 = 3440481107747
BaseRepresentation
bin10011001110101100001…
…010001110110101101001
311200022212122202010202020
4103032230022032311221
5133122303442320431
62451021312255053
7164320411626636
oct23165412166551
94608778663666
101321443323241
1146a46a340338
12194130841489
13977c480bba2
1447d5b41d18d
1524591742696
hex133ac28ed69

1321443323241 has 4 divisors (see below), whose sum is σ = 1761924430992. Its totient is φ = 880962215492.

The previous prime is 1321443323201. The next prime is 1321443323243. The reversal of 1321443323241 is 1423233441231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1321443323241 - 27 = 1321443323113 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1321443323243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220240553871 + ... + 220240553876.

It is an arithmetic number, because the mean of its divisors is an integer number (440481107748).

Almost surely, 21321443323241 is an apocalyptic number.

It is an amenable number.

1321443323241 is a deficient number, since it is larger than the sum of its proper divisors (440481107751).

1321443323241 is an equidigital number, since it uses as much as digits as its factorization.

1321443323241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440481107750.

The product of its digits is 41472, while the sum is 33.

Adding to 1321443323241 its reverse (1423233441231), we get a palindrome (2744676764472).

The spelling of 1321443323241 in words is "one trillion, three hundred twenty-one billion, four hundred forty-three million, three hundred twenty-three thousand, two hundred forty-one".

Divisors: 1 3 440481107747 1321443323241