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132151116451433 is a prime number
BaseRepresentation
bin11110000011000011010100…
…010110100100111001101001
3122022220112010112010021001112
4132003003110112210321221
5114310130441302421213
61145021215041000105
736556413600643322
oct3603032426447151
9568815115107045
10132151116451433
113911aa790786a2
12129a3931623035
135897a48789851
14248c2107c1449
15104284918aea8
hex7830d45a4e69

132151116451433 has 2 divisors, whose sum is σ = 132151116451434. Its totient is φ = 132151116451432.

The previous prime is 132151116451399. The next prime is 132151116451451. The reversal of 132151116451433 is 334154611151231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80552007155929 + 51599109295504 = 8975077^2 + 7183252^2 .

It is a cyclic number.

It is not a de Polignac number, because 132151116451433 - 218 = 132151116189289 is a prime.

It is not a weakly prime, because it can be changed into another prime (132151116451933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075558225716 + 66075558225717.

It is an arithmetic number, because the mean of its divisors is an integer number (66075558225717).

Almost surely, 2132151116451433 is an apocalyptic number.

It is an amenable number.

132151116451433 is a deficient number, since it is larger than the sum of its proper divisors (1).

132151116451433 is an equidigital number, since it uses as much as digits as its factorization.

132151116451433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129600, while the sum is 41.

The spelling of 132151116451433 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred sixteen million, four hundred fifty-one thousand, four hundred thirty-three".