13215402524243 has 4 divisors (see below), whose sum is σ = 13396435435608. Its totient is φ = 13034369612880.

The previous prime is 13215402524231. The next prime is 13215402524257. The reversal of 13215402524243 is 34242520451231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13215402524243 - 2⁴ = 13215402524227 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13215402524197 and 13215402524206.

It is not an unprimeable number, because it can be changed into a prime (13215402524273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90516455573 + ... + 90516455718.

It is an arithmetic number, because the mean of its divisors is an integer number (3349108858902).

Almost surely, 2^{13215402524243} is an apocalyptic number.

13215402524243 is a deficient number, since it is larger than the sum of its proper divisors (181032911365).

13215402524243 is an equidigital number, since it uses as much as digits as its factorization.

13215402524243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 181032911364.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 13215402524243 its reverse (34242520451231), we get a palindrome (47457922975474).

The spelling of 13215402524243 in words is "thirteen trillion, two hundred fifteen billion, four hundred two million, five hundred twenty-four thousand, two hundred forty-three".