13215552311041 has 4 divisors (see below), whose sum is σ = 13289382212400. Its totient is φ = 13141722409684.

The previous prime is 13215552310993. The next prime is 13215552311047. The reversal of 13215552311041 is 14011325551231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13215552311041 - 2²⁷ = 13215418093313 is a prime.

It is a super-2 number, since 2×13215552311041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13215552310988 and 13215552311006.

It is not an unprimeable number, because it can be changed into a prime (13215552311047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36914950411 + ... + 36914950768.

It is an arithmetic number, because the mean of its divisors is an integer number (3322345553100).

Almost surely, 2^{13215552311041} is an apocalyptic number.

It is an amenable number.

13215552311041 is a deficient number, since it is larger than the sum of its proper divisors (73829901359).

13215552311041 is an equidigital number, since it uses as much as digits as its factorization.

13215552311041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73829901358.

The product of its (nonzero) digits is 18000, while the sum is 34.

Adding to 13215552311041 its reverse (14011325551231), we get a palindrome (27226877862272).

The spelling of 13215552311041 in words is "thirteen trillion, two hundred fifteen billion, five hundred fifty-two million, three hundred eleven thousand, forty-one".