Base | Representation |
---|---|
bin | 11110000011000111100000… |
… | …011001100000001110111001 |
3 | 122022220221201221010122021202 |
4 | 132003013200121200032321 |
5 | 114310214144024401013 |
6 | 1145023241204343545 |
7 | 36556633205224034 |
oct | 3603074031401671 |
9 | 568827657118252 |
10 | 132155613512633 |
11 | 391219765a12a7 |
12 | 129a47876a4bb5 |
13 | 58982b43747c9 |
14 | 248c519b6401b |
15 | 1042a0dd98858 |
hex | 7831e06603b9 |
132155613512633 has 2 divisors, whose sum is σ = 132155613512634. Its totient is φ = 132155613512632.
The previous prime is 132155613512597. The next prime is 132155613512639. The reversal of 132155613512633 is 336215316551231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115478493272464 + 16677120240169 = 10746092^2 + 4083763^2 .
It is a cyclic number.
It is not a de Polignac number, because 132155613512633 - 26 = 132155613512569 is a prime.
It is not a weakly prime, because it can be changed into another prime (132155613512639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077806756316 + 66077806756317.
It is an arithmetic number, because the mean of its divisors is an integer number (66077806756317).
Almost surely, 2132155613512633 is an apocalyptic number.
It is an amenable number.
132155613512633 is a deficient number, since it is larger than the sum of its proper divisors (1).
132155613512633 is an equidigital number, since it uses as much as digits as its factorization.
132155613512633 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1458000, while the sum is 47.
The spelling of 132155613512633 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, six hundred thirteen million, five hundred twelve thousand, six hundred thirty-three".
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