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132174332531 is a prime number
BaseRepresentation
bin111101100011000110…
…1000100001001110011
3110122011110022210010022
41323012031010021303
54131143112120111
6140415310354055
712356255201153
oct1730615041163
9418143283108
10132174332531
1151066a6836a
1221748abb92b
13c6054ba227
14657c184763
153688bb02db
hex1ec6344273

132174332531 has 2 divisors, whose sum is σ = 132174332532. Its totient is φ = 132174332530.

The previous prime is 132174332513. The next prime is 132174332539. The reversal of 132174332531 is 135233471231.

Together with previous prime (132174332513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (135233471231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132174332531 - 226 = 132107223667 is a prime.

It is a super-2 number, since 2×1321743325312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132174332491 and 132174332500.

It is not a weakly prime, because it can be changed into another prime (132174332539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66087166265 + 66087166266.

It is an arithmetic number, because the mean of its divisors is an integer number (66087166266).

Almost surely, 2132174332531 is an apocalyptic number.

132174332531 is a deficient number, since it is larger than the sum of its proper divisors (1).

132174332531 is an equidigital number, since it uses as much as digits as its factorization.

132174332531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 45360, while the sum is 35.

The spelling of 132174332531 in words is "one hundred thirty-two billion, one hundred seventy-four million, three hundred thirty-two thousand, five hundred thirty-one".