Base | Representation |
---|---|
bin | 1100000001100000110010… |
… | …1100000001011101100001 |
3 | 1201210211110001021002101202 |
4 | 3000120030230001131201 |
5 | 3213044302241012001 |
6 | 44041123523210545 |
7 | 2533056644433236 |
oct | 300301454013541 |
9 | 51724401232352 |
10 | 13220122204001 |
11 | 4237693377659 |
12 | 1596194216a55 |
13 | 74b862a9b37b |
14 | 339c0071d78d |
15 | 17dd4446596b |
hex | c060cb01761 |
13220122204001 has 2 divisors, whose sum is σ = 13220122204002. Its totient is φ = 13220122204000.
The previous prime is 13220122203997. The next prime is 13220122204031. The reversal of 13220122204001 is 10040222102231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11997903512401 + 1222218691600 = 3463799^2 + 1105540^2 .
It is a cyclic number.
It is not a de Polignac number, because 13220122204001 - 22 = 13220122203997 is a prime.
It is not a weakly prime, because it can be changed into another prime (13220122204031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610061102000 + 6610061102001.
It is an arithmetic number, because the mean of its divisors is an integer number (6610061102001).
Almost surely, 213220122204001 is an apocalyptic number.
It is an amenable number.
13220122204001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13220122204001 is an equidigital number, since it uses as much as digits as its factorization.
13220122204001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13220122204001 its reverse (10040222102231), we get a palindrome (23260344306232).
The spelling of 13220122204001 in words is "thirteen trillion, two hundred twenty billion, one hundred twenty-two million, two hundred four thousand, one".
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