Base | Representation |
---|---|
bin | 10011001111001110000… |
… | …100110000000111001011 |
3 | 11200101100022101202121101 |
4 | 103033032010300013023 |
5 | 133124440122441021 |
6 | 2451153555522231 |
7 | 164340461146216 |
oct | 23171604600713 |
9 | 4611308352541 |
10 | 1322012312011 |
11 | 46a731537a96 |
12 | 19426b2b9377 |
13 | 9788566a431 |
14 | 47db2c1277d |
15 | 245c6686a91 |
hex | 133ce1301cb |
1322012312011 has 8 divisors (see below), whose sum is σ = 1391740089920. Its totient is φ = 1252299352392.
The previous prime is 1322012311993. The next prime is 1322012312069. The reversal of 1322012312011 is 1102132102231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1322012312011 - 217 = 1322012180939 is a prime.
It is a super-2 number, since 2×13220123120112 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1322012312011.
It is not an unprimeable number, because it can be changed into a prime (1322012372011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3521205 + ... + 3878518.
It is an arithmetic number, because the mean of its divisors is an integer number (173967511240).
Almost surely, 21322012312011 is an apocalyptic number.
1322012312011 is a deficient number, since it is larger than the sum of its proper divisors (69727777909).
1322012312011 is an equidigital number, since it uses as much as digits as its factorization.
1322012312011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7409145.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1322012312011 its reverse (1102132102231), we get a palindrome (2424144414242).
The spelling of 1322012312011 in words is "one trillion, three hundred twenty-two billion, twelve million, three hundred twelve thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •