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132201301201003 = 498865726500379
BaseRepresentation
bin11110000011110010000011…
…100110001101000001101011
3122100002022122222120200110001
4132003302003212031001223
5114311441231101413003
61145100234522203431
736563141325165466
oct3603620346150153
9570068588520401
10132201301201003
113913a291057841
12129b15b8353577
13589c6b58a4238
1424908118842dd
151043cd4d7661d
hex783c8398d06b

132201301201003 has 4 divisors (see below), whose sum is σ = 132201332690040. Its totient is φ = 132201269711968.

The previous prime is 132201301201001. The next prime is 132201301201019. The reversal of 132201301201003 is 300102103102231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132201301201003 - 21 = 132201301201001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132201301201001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8261533 + ... + 18238846.

It is an arithmetic number, because the mean of its divisors is an integer number (33050333172510).

Almost surely, 2132201301201003 is an apocalyptic number.

132201301201003 is a deficient number, since it is larger than the sum of its proper divisors (31489037).

132201301201003 is an equidigital number, since it uses as much as digits as its factorization.

132201301201003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31489036.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 132201301201003 its reverse (300102103102231), we get a palindrome (432303404303234).

The spelling of 132201301201003 in words is "one hundred thirty-two trillion, two hundred one billion, three hundred one million, two hundred one thousand, three".

Divisors: 1 4988657 26500379 132201301201003