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1322014000341 = 35996067121259
BaseRepresentation
bin10011001111001110001…
…011001100010011010101
311200101100102120112120010
4103033032023030103111
5133124441041002331
62451154100030433
7164340511410366
oct23171613142325
94611312515503
101322014000341
1146a732490501
1219426b992419
1397885b0ba48
1447db3131b6d
15245c68bbe46
hex133ce2cc4d5

1322014000341 has 16 divisors (see below), whose sum is σ = 1765933632000. Its totient is φ = 879719029488.

The previous prime is 1322014000309. The next prime is 1322014000393. The reversal of 1322014000341 is 1430004102231.

It is not a de Polignac number, because 1322014000341 - 25 = 1322014000309 is a prime.

It is a super-2 number, since 2×13220140003412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1322014000141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10841770 + ... + 10963028.

It is an arithmetic number, because the mean of its divisors is an integer number (110370852000).

Almost surely, 21322014000341 is an apocalyptic number.

It is an amenable number.

1322014000341 is a deficient number, since it is larger than the sum of its proper divisors (443919631659).

1322014000341 is a wasteful number, since it uses less digits than its factorization.

1322014000341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127928.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1322014000341 its reverse (1430004102231), we get a palindrome (2752018102572).

The spelling of 1322014000341 in words is "one trillion, three hundred twenty-two billion, fourteen million, three hundred forty-one", and thus it is an aban number.

Divisors: 1 3 599 1797 6067 18201 121259 363777 3634133 10902399 72634141 217902423 735678353 2207035059 440671333447 1322014000341