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132202340312641 = 613215664502957
BaseRepresentation
bin11110000011110011000001…
…100010000110011001000001
3122100002102100101212000122021
4132003303001202012121001
5114312000343110001031
61145100530002041441
736563206143404464
oct3603630142063101
9570072311760567
10132202340312641
113913a774664795
12129b1848349281
13589c81cc567b1
1424908ad8932db
151043d461d1511
hex783cc1886641

132202340312641 has 4 divisors (see below), whose sum is σ = 132418004816212. Its totient is φ = 131986675809072.

The previous prime is 132202340312621. The next prime is 132202340312683. The reversal of 132202340312641 is 146213043202231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17384771945025 + 114817568367616 = 4169505^2 + 10715296^2 .

It is a cyclic number.

It is not a de Polignac number, because 132202340312641 - 29 = 132202340312129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132202340312597 and 132202340312606.

It is not an unprimeable number, because it can be changed into a prime (132202340312621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107832250866 + ... + 107832252091.

It is an arithmetic number, because the mean of its divisors is an integer number (33104501204053).

Almost surely, 2132202340312641 is an apocalyptic number.

It is an amenable number.

132202340312641 is a deficient number, since it is larger than the sum of its proper divisors (215664503571).

132202340312641 is an equidigital number, since it uses as much as digits as its factorization.

132202340312641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215664503570.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 132202340312641 its reverse (146213043202231), we get a palindrome (278415383514872).

The spelling of 132202340312641 in words is "one hundred thirty-two trillion, two hundred two billion, three hundred forty million, three hundred twelve thousand, six hundred forty-one".

Divisors: 1 613 215664502957 132202340312641