Base | Representation |
---|---|
bin | 10011001111001111111… |
… | …011000010100001010001 |
3 | 11200101102110202011010021 |
4 | 103033033323002201101 |
5 | 133130021042223101 |
6 | 2451201024303441 |
7 | 164341315544536 |
oct | 23171773024121 |
9 | 4611373664107 |
10 | 1322043320401 |
11 | 46a747a97061 |
12 | 194279771b81 |
13 | 9788bc063ab |
14 | 47db6da4d8d |
15 | 245c925e5a1 |
hex | 133cfec2851 |
1322043320401 has 2 divisors, whose sum is σ = 1322043320402. Its totient is φ = 1322043320400.
The previous prime is 1322043320393. The next prime is 1322043320417. The reversal of 1322043320401 is 1040233402231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 672729680401 + 649313640000 = 820201^2 + 805800^2 .
It is a cyclic number.
It is not a de Polignac number, because 1322043320401 - 23 = 1322043320393 is a prime.
It is a super-2 number, since 2×13220433204012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1322043320471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661021660200 + 661021660201.
It is an arithmetic number, because the mean of its divisors is an integer number (661021660201).
Almost surely, 21322043320401 is an apocalyptic number.
It is an amenable number.
1322043320401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322043320401 is an equidigital number, since it uses as much as digits as its factorization.
1322043320401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 1322043320401 its reverse (1040233402231), we get a palindrome (2362276722632).
The spelling of 1322043320401 in words is "one trillion, three hundred twenty-two billion, forty-three million, three hundred twenty thousand, four hundred one".
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