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132211110320017 is a prime number
BaseRepresentation
bin11110000011111011001100…
…010001000001011110010001
3122100010020222121011120002021
4132003323030101001132101
5114312121323220220032
61145104540125451441
736563636364263221
oct3603731421013621
9570106877146067
10132211110320017
1139143465048073
12129b3495410b81
1358a05b9b7ac81
1424910a251a081
1510441ab0cc097
hex783ecc441791

132211110320017 has 2 divisors, whose sum is σ = 132211110320018. Its totient is φ = 132211110320016.

The previous prime is 132211110319993. The next prime is 132211110320039. The reversal of 132211110320017 is 710023011112231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109251641427201 + 22959468892816 = 10452351^2 + 4791604^2 .

It is a cyclic number.

It is not a de Polignac number, because 132211110320017 - 231 = 132208962836369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132211110319973 and 132211110320000.

It is not a weakly prime, because it can be changed into another prime (132211110320117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66105555160008 + 66105555160009.

It is an arithmetic number, because the mean of its divisors is an integer number (66105555160009).

Almost surely, 2132211110320017 is an apocalyptic number.

It is an amenable number.

132211110320017 is a deficient number, since it is larger than the sum of its proper divisors (1).

132211110320017 is an equidigital number, since it uses as much as digits as its factorization.

132211110320017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 132211110320017 its reverse (710023011112231), we get a palindrome (842234121432248).

The spelling of 132211110320017 in words is "one hundred thirty-two trillion, two hundred eleven billion, one hundred ten million, three hundred twenty thousand, seventeen".