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132211312039057 is a prime number
BaseRepresentation
bin11110000011111011011000…
…010010100001010010010001
3122100010021111122201221120211
4132003323120102201102101
5114312122231340222212
61145105012133204121
736563644364000326
oct3603733022412221
9570107448657524
10132211312039057
11391435589a4619
12129b3530a90641
1358a061c8b7854
1424910c1228b4d
1510441bdb759a7
hex783ed84a1491

132211312039057 has 2 divisors, whose sum is σ = 132211312039058. Its totient is φ = 132211312039056.

The previous prime is 132211312039003. The next prime is 132211312039067. The reversal of 132211312039057 is 750930213112231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116712673716496 + 15498638322561 = 10803364^2 + 3936831^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132211312039057 is a prime.

It is not a weakly prime, because it can be changed into another prime (132211312039067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66105656019528 + 66105656019529.

It is an arithmetic number, because the mean of its divisors is an integer number (66105656019529).

Almost surely, 2132211312039057 is an apocalyptic number.

It is an amenable number.

132211312039057 is a deficient number, since it is larger than the sum of its proper divisors (1).

132211312039057 is an equidigital number, since it uses as much as digits as its factorization.

132211312039057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 68040, while the sum is 40.

The spelling of 132211312039057 in words is "one hundred thirty-two trillion, two hundred eleven billion, three hundred twelve million, thirty-nine thousand, fifty-seven".