Base | Representation |
---|---|
bin | 11110000011111011011000… |
… | …010010100001010010010001 |
3 | 122100010021111122201221120211 |
4 | 132003323120102201102101 |
5 | 114312122231340222212 |
6 | 1145105012133204121 |
7 | 36563644364000326 |
oct | 3603733022412221 |
9 | 570107448657524 |
10 | 132211312039057 |
11 | 391435589a4619 |
12 | 129b3530a90641 |
13 | 58a061c8b7854 |
14 | 24910c1228b4d |
15 | 10441bdb759a7 |
hex | 783ed84a1491 |
132211312039057 has 2 divisors, whose sum is σ = 132211312039058. Its totient is φ = 132211312039056.
The previous prime is 132211312039003. The next prime is 132211312039067. The reversal of 132211312039057 is 750930213112231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116712673716496 + 15498638322561 = 10803364^2 + 3936831^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132211312039057 is a prime.
It is not a weakly prime, because it can be changed into another prime (132211312039067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66105656019528 + 66105656019529.
It is an arithmetic number, because the mean of its divisors is an integer number (66105656019529).
Almost surely, 2132211312039057 is an apocalyptic number.
It is an amenable number.
132211312039057 is a deficient number, since it is larger than the sum of its proper divisors (1).
132211312039057 is an equidigital number, since it uses as much as digits as its factorization.
132211312039057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 132211312039057 in words is "one hundred thirty-two trillion, two hundred eleven billion, three hundred twelve million, thirty-nine thousand, fifty-seven".
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