Base | Representation |
---|---|
bin | 111101100100001101… |
… | …0100101101001100001 |
3 | 110122021001010122001221 |
4 | 1323020122211221201 |
5 | 4131232111311113 |
6 | 140423113455041 |
7 | 12360215426032 |
oct | 1731032455141 |
9 | 418231118057 |
10 | 132211432033 |
11 | 510859a780a |
12 | 21759411481 |
13 | c6100a97b5 |
14 | 6583080a89 |
15 | 368c08c98d |
hex | 1ec86a5a61 |
132211432033 has 4 divisors (see below), whose sum is σ = 132217602048. Its totient is φ = 132205262020.
The previous prime is 132211432027. The next prime is 132211432051. The reversal of 132211432033 is 330234112231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132211432033 - 217 = 132211300961 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132211431989 and 132211432007.
It is not an unprimeable number, because it can be changed into a prime (132211430033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3052753 + ... + 3095758.
It is an arithmetic number, because the mean of its divisors is an integer number (33054400512).
Almost surely, 2132211432033 is an apocalyptic number.
It is an amenable number.
132211432033 is a deficient number, since it is larger than the sum of its proper divisors (6170015).
132211432033 is an equidigital number, since it uses as much as digits as its factorization.
132211432033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6170014.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 132211432033 its reverse (330234112231), we get a palindrome (462445544264).
The spelling of 132211432033 in words is "one hundred thirty-two billion, two hundred eleven million, four hundred thirty-two thousand, thirty-three".
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