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132212011130323 is a prime number
BaseRepresentation
bin11110000011111100000001…
…111101010101110111010011
3122100010100022101012110111221
4132003330001331111313103
5114312130144322132243
61145105205345145511
736564000613115305
oct3603740175256723
9570110271173457
10132212011130323
11391438875831a3
12129b36a702b297
1358a0701699417
14249114a007975
151044210218bed
hex783f01f55dd3

132212011130323 has 2 divisors, whose sum is σ = 132212011130324. Its totient is φ = 132212011130322.

The previous prime is 132212011130249. The next prime is 132212011130347. The reversal of 132212011130323 is 323031110212231.

It is a strong prime.

It is an emirp because it is prime and its reverse (323031110212231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132212011130323 - 221 = 132212009033171 is a prime.

It is a super-3 number, since 3×1322120111303233 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132212011130393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106005565161 + 66106005565162.

It is an arithmetic number, because the mean of its divisors is an integer number (66106005565162).

Almost surely, 2132212011130323 is an apocalyptic number.

132212011130323 is a deficient number, since it is larger than the sum of its proper divisors (1).

132212011130323 is an equidigital number, since it uses as much as digits as its factorization.

132212011130323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 132212011130323 its reverse (323031110212231), we get a palindrome (455243121342554).

The spelling of 132212011130323 in words is "one hundred thirty-two trillion, two hundred twelve billion, eleven million, one hundred thirty thousand, three hundred twenty-three".