Base | Representation |
---|---|
bin | 111101100100001110… |
… | …1100011100111010011 |
3 | 110122021002121011102101 |
4 | 1323020131203213103 |
5 | 4131232311211011 |
6 | 140423142301231 |
7 | 12360225146401 |
oct | 1731035434723 |
9 | 418232534371 |
10 | 132212210131 |
11 | 51086389371 |
12 | 21759727817 |
13 | c6102bca01 |
14 | 6583204471 |
15 | 368c1932c1 |
hex | 1ec87639d3 |
132212210131 has 4 divisors (see below), whose sum is σ = 132218831200. Its totient is φ = 132205589064.
The previous prime is 132212210111. The next prime is 132212210147. The reversal of 132212210131 is 131012212231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132212210131 - 25 = 132212210099 is a prime.
It is a super-2 number, since 2×1322122101312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132212210099 and 132212210108.
It is not an unprimeable number, because it can be changed into a prime (132212210111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3280491 + ... + 3320548.
It is an arithmetic number, because the mean of its divisors is an integer number (33054707800).
Almost surely, 2132212210131 is an apocalyptic number.
132212210131 is a deficient number, since it is larger than the sum of its proper divisors (6621069).
132212210131 is an equidigital number, since it uses as much as digits as its factorization.
132212210131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6621068.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 132212210131 its reverse (131012212231), we get a palindrome (263224422362).
The spelling of 132212210131 in words is "one hundred thirty-two billion, two hundred twelve million, two hundred ten thousand, one hundred thirty-one".
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