Base | Representation |
---|---|
bin | 11110000011111100001111… |
… | …101011001001111101100011 |
3 | 122100010100220102012110010211 |
4 | 132003330033223021331203 |
5 | 114312131132224302003 |
6 | 1145105244245234551 |
7 | 36564006406053544 |
oct | 3603741753117543 |
9 | 570110812173124 |
10 | 132212241244003 |
11 | 39143995463a98 |
12 | 129b3750102a57 |
13 | 58a073a26836b |
14 | 249116c7c84cb |
15 | 104422552096d |
hex | 783f0fac9f63 |
132212241244003 has 4 divisors (see below), whose sum is σ = 132221235900600. Its totient is φ = 132203246587408.
The previous prime is 132212241243923. The next prime is 132212241244073. The reversal of 132212241244003 is 300442142212231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132212241244003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132212241244073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4497306250 + ... + 4497335647.
It is an arithmetic number, because the mean of its divisors is an integer number (33055308975150).
Almost surely, 2132212241244003 is an apocalyptic number.
132212241244003 is a deficient number, since it is larger than the sum of its proper divisors (8994656597).
132212241244003 is an equidigital number, since it uses as much as digits as its factorization.
132212241244003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8994656596.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 132212241244003 its reverse (300442142212231), we get a palindrome (432654383456234).
The spelling of 132212241244003 in words is "one hundred thirty-two trillion, two hundred twelve billion, two hundred forty-one million, two hundred forty-four thousand, three".
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