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132213112223113 is a prime number
BaseRepresentation
bin11110000011111101000011…
…100101101011010110001001
3122100010110011010002202212101
4132003331003211223112021
5114312134423212114423
61145105510521313401
736564040113212335
oct3603750345532611
9570113133082771
10132213112223113
11391442a2074539
12129b3953935861
1358a084884060c
14249121234c7c5
151044276c187ad
hex783f4396b589

132213112223113 has 2 divisors, whose sum is σ = 132213112223114. Its totient is φ = 132213112223112.

The previous prime is 132213112223077. The next prime is 132213112223117. The reversal of 132213112223113 is 311322211312231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126609911939449 + 5603200283664 = 11252107^2 + 2367108^2 .

It is a cyclic number.

It is not a de Polignac number, because 132213112223113 - 229 = 132212575352201 is a prime.

It is a super-3 number, since 3×1322131122231133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132213112223117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106556111556 + 66106556111557.

It is an arithmetic number, because the mean of its divisors is an integer number (66106556111557).

Almost surely, 2132213112223113 is an apocalyptic number.

It is an amenable number.

132213112223113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132213112223113 is an equidigital number, since it uses as much as digits as its factorization.

132213112223113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 28.

Adding to 132213112223113 its reverse (311322211312231), we get a palindrome (443535323535344).

The spelling of 132213112223113 in words is "one hundred thirty-two trillion, two hundred thirteen billion, one hundred twelve million, two hundred twenty-three thousand, one hundred thirteen".