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13221433412251 is a prime number
BaseRepresentation
bin1100000001100101101011…
…0101111000101010011011
31201210221211102112100222021
43000121122311320222123
53213104443423143001
644041502003035311
72533134305504641
oct300313265705233
951727742470867
1013221433412251
1142381a652a839
12159649b36bb37
1374ba1162bb3c
14339cc691b191
1517ddbe61bba1
hexc065ad78a9b

13221433412251 has 2 divisors, whose sum is σ = 13221433412252. Its totient is φ = 13221433412250.

The previous prime is 13221433412207. The next prime is 13221433412359. The reversal of 13221433412251 is 15221433412231.

13221433412251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (15221433412231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13221433412251 - 211 = 13221433410203 is a prime.

It is not a weakly prime, because it can be changed into another prime (13221463412251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610716706125 + 6610716706126.

It is an arithmetic number, because the mean of its divisors is an integer number (6610716706126).

Almost surely, 213221433412251 is an apocalyptic number.

13221433412251 is a deficient number, since it is larger than the sum of its proper divisors (1).

13221433412251 is an equidigital number, since it uses as much as digits as its factorization.

13221433412251 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 34.

Adding to 13221433412251 its reverse (15221433412231), we get a palindrome (28442866824482).

The spelling of 13221433412251 in words is "thirteen trillion, two hundred twenty-one billion, four hundred thirty-three million, four hundred twelve thousand, two hundred fifty-one".