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132214662124241 is a prime number
BaseRepresentation
bin11110000011111110011111…
…111110000101001011010001
3122100010121011010111220111212
4132003332133332011023101
5114312201112000433431
61145110324405145505
736564123403153454
oct3603763776051321
9570117133456455
10132214662124241
1139144a17a38164
12129b41069bb295
1358a0a34984c88
14249131c12149b
151044317d1d72b
hex783f9ff852d1

132214662124241 has 2 divisors, whose sum is σ = 132214662124242. Its totient is φ = 132214662124240.

The previous prime is 132214662124217. The next prime is 132214662124253. The reversal of 132214662124241 is 142421266412231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121905425484241 + 10309236640000 = 11041079^2 + 3210800^2 .

It is an emirp because it is prime and its reverse (142421266412231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132214662124241 - 210 = 132214662123217 is a prime.

It is not a weakly prime, because it can be changed into another prime (132214662124201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107331062120 + 66107331062121.

It is an arithmetic number, because the mean of its divisors is an integer number (66107331062121).

Almost surely, 2132214662124241 is an apocalyptic number.

It is an amenable number.

132214662124241 is a deficient number, since it is larger than the sum of its proper divisors (1).

132214662124241 is an equidigital number, since it uses as much as digits as its factorization.

132214662124241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 221184, while the sum is 41.

The spelling of 132214662124241 in words is "one hundred thirty-two trillion, two hundred fourteen billion, six hundred sixty-two million, one hundred twenty-four thousand, two hundred forty-one".