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132215131416217 is a prime number
BaseRepresentation
bin11110000011111110111011…
…111100010010011010011001
3122100010122100211120102002011
4132003332323330102122121
5114312203042120304332
61145110443131505521
736564141132112603
oct3603767374223231
9570118324512064
10132215131416217
1139145138930173
12129b4217bb82a1
1358a0aaac77a35
1424913645a2173
15104434411ce47
hex783fbbf12699

132215131416217 has 2 divisors, whose sum is σ = 132215131416218. Its totient is φ = 132215131416216.

The previous prime is 132215131416157. The next prime is 132215131416227. The reversal of 132215131416217 is 712614131512231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89786635287561 + 42428496128656 = 9475581^2 + 6513716^2 .

It is a cyclic number.

It is not a de Polignac number, because 132215131416217 - 211 = 132215131414169 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132215131416217.

It is not a weakly prime, because it can be changed into another prime (132215131416227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107565708108 + 66107565708109.

It is an arithmetic number, because the mean of its divisors is an integer number (66107565708109).

Almost surely, 2132215131416217 is an apocalyptic number.

It is an amenable number.

132215131416217 is a deficient number, since it is larger than the sum of its proper divisors (1).

132215131416217 is an equidigital number, since it uses as much as digits as its factorization.

132215131416217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 40.

Adding to 132215131416217 its reverse (712614131512231), we get a palindrome (844829262928448).

The spelling of 132215131416217 in words is "one hundred thirty-two trillion, two hundred fifteen billion, one hundred thirty-one million, four hundred sixteen thousand, two hundred seventeen".