Base | Representation |
---|---|
bin | 11110000011111110111100… |
… | …101000101101011010011011 |
3 | 122100010122101122111000220212 |
4 | 132003332330220231122123 |
5 | 114312203103110424042 |
6 | 1145110444225241335 |
7 | 36564141333103046 |
oct | 3603767450553233 |
9 | 570118348430825 |
10 | 132215143061147 |
11 | 39145144464183 |
12 | 129b421ba9324b |
13 | 58a0ab04c4223 |
14 | 2491365d53c5d |
15 | 104434516d482 |
hex | 783fbca2d69b |
132215143061147 has 2 divisors, whose sum is σ = 132215143061148. Its totient is φ = 132215143061146.
The previous prime is 132215143061107. The next prime is 132215143061167. The reversal of 132215143061147 is 741160341512231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132215143061147 - 220 = 132215142012571 is a prime.
It is not a weakly prime, because it can be changed into another prime (132215143061107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107571530573 + 66107571530574.
It is an arithmetic number, because the mean of its divisors is an integer number (66107571530574).
Almost surely, 2132215143061147 is an apocalyptic number.
132215143061147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132215143061147 is an equidigital number, since it uses as much as digits as its factorization.
132215143061147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 41.
Adding to 132215143061147 its reverse (741160341512231), we get a palindrome (873375484573378).
The spelling of 132215143061147 in words is "one hundred thirty-two trillion, two hundred fifteen billion, one hundred forty-three million, sixty-one thousand, one hundred forty-seven".
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