Base | Representation |
---|---|
bin | 1100000001100110000000… |
… | …0100001000100000010011 |
3 | 1201210222001112101222100220 |
4 | 3000121200010020200103 |
5 | 3213110133341030420 |
6 | 44041514413044123 |
7 | 2533136421331464 |
oct | 300314004104023 |
9 | 51728045358326 |
10 | 13221521033235 |
11 | 4238240a36779 |
12 | 1596504786643 |
13 | 74ba26829c88 |
14 | 339cd4408d6b |
15 | 17ddc7178840 |
hex | c0660108813 |
13221521033235 has 16 divisors (see below), whose sum is σ = 22267824898560. Its totient is φ = 6680347469280.
The previous prime is 13221521033219. The next prime is 13221521033249. The reversal of 13221521033235 is 53233012512231.
It is not a de Polignac number, because 13221521033235 - 24 = 13221521033219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13221521033196 and 13221521033205.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23195650651 + ... + 23195651220.
It is an arithmetic number, because the mean of its divisors is an integer number (1391739056160).
Almost surely, 213221521033235 is an apocalyptic number.
13221521033235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13221521033235 is a deficient number, since it is larger than the sum of its proper divisors (9046303865325).
13221521033235 is a wasteful number, since it uses less digits than its factorization.
13221521033235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46391301898.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13221521033235 its reverse (53233012512231), we get a palindrome (66454533545466).
The spelling of 13221521033235 in words is "thirteen trillion, two hundred twenty-one billion, five hundred twenty-one million, thirty-three thousand, two hundred thirty-five".
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