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132216140648353 is a prime number
BaseRepresentation
bin11110000011111111111000…
…000110001100111110100001
3122100010201222011121201022011
4132003333320012030332201
5114312212124001221403
61145111131223112521
736564205135334416
oct3603777006147641
9570121864551264
10132216140648353
113914560658a213
12129b4459ba2741
1358a0c0c098108
14249141c63410d
1510443a2a24a6d
hex783ff818cfa1

132216140648353 has 2 divisors, whose sum is σ = 132216140648354. Its totient is φ = 132216140648352.

The previous prime is 132216140648327. The next prime is 132216140648419. The reversal of 132216140648353 is 353846041612231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104009239074064 + 28206901574289 = 10198492^2 + 5311017^2 .

It is a cyclic number.

It is not a de Polignac number, because 132216140648353 - 221 = 132216138551201 is a prime.

It is a super-2 number, since 2×1322161406483532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132216140648297 and 132216140648306.

It is not a weakly prime, because it can be changed into another prime (132216140648653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66108070324176 + 66108070324177.

It is an arithmetic number, because the mean of its divisors is an integer number (66108070324177).

Almost surely, 2132216140648353 is an apocalyptic number.

It is an amenable number.

132216140648353 is a deficient number, since it is larger than the sum of its proper divisors (1).

132216140648353 is an equidigital number, since it uses as much as digits as its factorization.

132216140648353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2488320, while the sum is 49.

The spelling of 132216140648353 in words is "one hundred thirty-two trillion, two hundred sixteen billion, one hundred forty million, six hundred forty-eight thousand, three hundred fifty-three".