Base | Representation |
---|---|
bin | 111101100100010110… |
… | …0111101000010110011 |
3 | 110122021101012020012201 |
4 | 1323020230331002303 |
5 | 4131234324341301 |
6 | 140423405004031 |
7 | 12360304360162 |
oct | 1731054750263 |
9 | 418241166181 |
10 | 132216246451 |
11 | 51088695973 |
12 | 2175ab53617 |
13 | c6110a3c73 |
14 | 65839753d9 |
15 | 368c6de201 |
hex | 1ec8b3d0b3 |
132216246451 has 4 divisors (see below), whose sum is σ = 132217845304. Its totient is φ = 132214647600.
The previous prime is 132216246397. The next prime is 132216246457. The reversal of 132216246451 is 154642612231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132216246451 is a prime.
It is a super-2 number, since 2×1322162464512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 132216246451.
It is not an unprimeable number, because it can be changed into a prime (132216246457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668205 + ... + 843166.
It is an arithmetic number, because the mean of its divisors is an integer number (33054461326).
Almost surely, 2132216246451 is an apocalyptic number.
132216246451 is a deficient number, since it is larger than the sum of its proper divisors (1598853).
132216246451 is an equidigital number, since it uses as much as digits as its factorization.
132216246451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1598852.
The product of its digits is 69120, while the sum is 37.
Adding to 132216246451 its reverse (154642612231), we get a palindrome (286858858682).
The spelling of 132216246451 in words is "one hundred thirty-two billion, two hundred sixteen million, two hundred forty-six thousand, four hundred fifty-one".
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