Base | Representation |
---|---|
bin | 11110000100000011100101… |
… | …011011011100000010010101 |
3 | 122100011010020200000102122022 |
4 | 132010003211123130002111 |
5 | 114312243302314242003 |
6 | 1145113030302142525 |
7 | 36564405614651315 |
oct | 3604034533340225 |
9 | 570133220012568 |
10 | 132220122415253 |
11 | 3914726a14a664 |
12 | 129b518b581a45 |
13 | 58a13c4ca46c2 |
14 | 24916b939d445 |
15 | 1044537397738 |
hex | 7840e56dc095 |
132220122415253 has 16 divisors (see below), whose sum is σ = 132971761878336. Its totient is φ = 131471134502400.
The previous prime is 132220122415201. The next prime is 132220122415379. The reversal of 132220122415253 is 352514221022231.
It is a cyclic number.
It is not a de Polignac number, because 132220122415253 - 218 = 132220122153109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132220122415153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 178584278 + ... + 179323128.
It is an arithmetic number, because the mean of its divisors is an integer number (8310735117396).
Almost surely, 2132220122415253 is an apocalyptic number.
It is an amenable number.
132220122415253 is a deficient number, since it is larger than the sum of its proper divisors (751639463083).
132220122415253 is an equidigital number, since it uses as much as digits as its factorization.
132220122415253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 740644.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 132220122415253 its reverse (352514221022231), we get a palindrome (484734343437484).
The spelling of 132220122415253 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-two million, four hundred fifteen thousand, two hundred fifty-three".
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